# 编写一个函数，其作用是将输入的字符串反转过来。输入字符串以字符数组 char[] 的形式给出。 
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#  不要给另外的数组分配额外的空间，你必须原地修改输入数组、使用 O(1) 的额外空间解决这一问题。 
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#  你可以假设数组中的所有字符都是 ASCII 码表中的可打印字符。 
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#  示例 1： 
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#  输入：["h","e","l","l","o"]
# 输出：["o","l","l","e","h"]
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#  示例 2： 
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#  输入：["H","a","n","n","a","h"]
# 输出：["h","a","n","n","a","H"] 
#  Related Topics 双指针 字符串 
#  👍 297 👎 0


# leetcode submit region begin(Prohibit modification and deletion)
class Solution:
    def reverseString(self, s: List[str]) -> None:
        """
        Do not return anything, modify s in-place instead.
        """
        n = len(s)
        for i in range(0, n//2):
            s[i], s[n-1-i] = s[n-1-i], s[i]
# leetcode submit region end(Prohibit modification and deletion)
